Solve For X Word Problems

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Now let’s do some problems that use some of the translations above.

We’ll get to more difficult algebra word problems later. Solution: We always have to define a variable, and we can look at what they are asking.

This article was co-authored by our trained team of editors and researchers who validated it for accuracy and comprehensiveness. Deborah has $88.50, and Colin has $61.50, which together add up to $150.

Together, they cited information from 10 references.

So, you need to calculate: 3(340)=1,020 He uses 1,020 grams. So, the sum of the money received for bracelets, rings, and necklaces, will equal 245: 5x 20x 15x 45=245 So, you have one equation that you can solve for x, which is the number of bracelets sold: 5x 20x 15x 45=245 40x 45=245 40x=200 x=5 Remember that x equals the number of bracelets sold.

But, you cannot simply subtract this from the total mass of the bag of flour, because the bag of flour is stated in kilograms. 2.27(1000)= 2270 grams Now, subtract the amount of grams of flour Oliver used from the total grams in the bag of flour: 2,270-1,020=1,250 5. So, the amount of money she makes from bracelets is given by the expression 5x. The problem asks you to find the number of bracelets, rings, and necklaces sold. Sarah is an educator and writer with a Master’s degree in education from Syracuse University who has helped students succeed on standardized tests since 2008.You’ll need to translate English into “mathematical language” in order to make sure you set up your equations correctly, including variables and operations. Audrey earns money each week by tutoring and by babysitting. How many hours does she tutor, and how many hours does she babysit? D) She tutors for 3 hours and babysits for 2 hours. Oliver needs 340 grams of flour to make one batch of his biscuit recipe. If he makes three batches of biscuits, how many grams of flour will he have left? A) 8 necklaces, 5 bracelets, and 10 rings B) 5 necklaces, 10 bracelets, and 8 rings C) 10 necklaces, 8 bracelets, and 5 rings D) 5 necklaces, 8 bracelets, and 10 rings 1.To help you practice, here are five challenging GED algebra word problems. He buys a new car that is ,600 less than five times the selling price of his old car. She charges an hour for tutoring, and an hour for babysitting. A) 1,020 grams B) 1,190 grams C) 1,250 grams D) 1,930 grams 5. B You need to find three numbers that will add up to 111.(x) (x 1) (x 2)=111 3x 1 2=111 3x 3=111 If you wanted to solve for x, you would isolate the variable by subtracting 3 from both sides, then dividing by 3: 3x 3=111 3x=108 x=36 So, the 3 consecutive integers are 36, 37, and 38. A This problem involves translating the words into mathematical expressions.The first equation is quite simple to set up, since you know that she works 5 hours each week: x y=5 Use the information about the money Audrey earns to set up the second equation.However, word problems can present a real challenge if you don't know how to break them down and find the numbers underneath the story. Solving word problems is an art of transforming the words and sentences into mathematical expressions and then applying conventional algebraic techniques to solve the problem. You also know that she makes an hour babysitting, and you already stated that the number of hours she babysits each week is y.So, the expression describing how much she makes each week babysitting is 15y. So, your second equation tells you how to calculate the amount of money she earns weekly: 30x 15y=120 You can simplify this equation by dividing each term by 15: 2x y=8 So, you now have your two equations and can solve: x y=5 2x y=8 Isolate the x variable in the first equation: x y=5 x=5-y Now, substitute this expression ofx into the second equation and solve for y: 2x y=8 2(5-y) y=8 10-2y y=8 10-y=8 -y=-2 y=2 So, she babysits for 2 hours each week. So, the amount of money she makes from necklaces is given by the expression It might help to make a table to help you organize all of the information in this problem.The problem is asking for both the numbers, so we can make “\(n\)” the smaller number, and “\(18-n\)” the larger.\(\begin2n-3\,\,\,=\,\,18-n\\underline\3n\,-3\,\,=\,\,\,18\\underline\\,\,3n\,\,\,\,\,\,\,\,\,\,=\,\,\,21\\,\frac\,\,\,\,\,\,\,\,\,\,\,=\,\,\frac\\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,n=7\,\,\,\,\,\,\text\\,\,\,18-7=11\,\,\,\,\text\end\) Solution: We always have to define a variable, and we can look at what they are asking.

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